Determine the volume of hydrogen and the mass of oxygen formed during the decomposition of 19 g of water containing 15% impurities.

Given:
m mixture (H2O) = 19 g
w approx (H2O) = 15%
To find:
V (H2)
V (O2)
Decision:
2H2O = 2H2 + O2
w h.in (H2O) = 100% -15% = 85% = 0.85
m in (H2O) = w hours in * m mixture = 0.85 * 19 g = 16.15 g
n (H2O) = m / M = 16.15 g / 18 g / mol = 0.9 mol
n (H2O): n (H2) = 1: 1
n (H2) = 0.9 mol
n (H2O): n (O2) = 2: 1
n (O2) = 0.9 mol / 2 = 0.45 mol
V (H2) = n * Vm = 0.9 mol * 22.4 L / mol = 20.16 L
V (O2) = n * Vm = 0.45 mol * 22.4 L / mol = 10.08 L
Answer: 20.16 l; 10.08 l