Determine the volume of hydrogen chloride obtained by the interaction of 4 mol of hydrogen with an excess of chlorine.

Answer: 179.2 l.
Explanation: to solve this problem, you first need to write the equation for the chemical reaction of the interaction of hydrogen with chlorine:
H2 + Cl2 = 2HCl.
Then you need to find the amount of hydrochloric acid substance, it will be 2 times more than the amount of hydrogen substance, because the reaction shows that they are in a ratio of 2: 1, respectively:
n (HCl) = 2 * n (H2) = 2 * 4 = 8 mol.
The last step is to find the volume of hydrochloric acid by multiplying its amount of substance by the molar volume:
V (HCl) = 8 * 22.4 = 179.2 l.