Determine the volume of hydrogen formed by the interaction of 146 g of hydrochloric acid with zinc weighing 195 g.

Zinc reacts with hydrochloric acid to release hydrogen gas and form zinc chloride.

Zn + 2HCl = ZnCl2 + H2;

1 mole of zinc reacts with 2 moles of acid. In this case, 1 mol of salt is formed and 1 mol of hydrogen gas is released.

Let’s calculate the available chemical amount of zinc. To do this, divide the weight of pure metal by the weight of 1 mole of metallic zinc.

M Zn = 65 grams / mol; N Zn = 195/65 = 3 mol;

Let’s calculate the chemical amount of a substance in 146 grams of hydrochloric acid. To do this, divide the weight of the substance by the weight of 1 mole of the substance.

M HCl = 1 + 35.5 = 36.5 grams / mol; N HCl = 146 / 36.5 = 4 mol;

When reacting with such an amount of acid, 2 times less hydrogen will be synthesized.

Let’s calculate the volume of hydrogen. To do this, multiply the amount of substance by the volume of 1 mole of gas, which is 22.4 liters.

N H2 = 4/2 = 2 mol; V H2 = 2 x 22.4 = 44.8 liters;