Determine the volume of hydrogen (H2) that will be released when 19.5 zinc (Zn) reacts with hydrochloric acid.

When dissolved in hydrochloric acid, metallic zinc is converted to zinc chloride.

Zn + 2HCl = ZnCl2 + H2;

Let’s calculate the molar amount of metallic zinc. To do this, divide its weight by the mass of 1 mole of metal.

N Zn = 19.5 / 65 = 0.3 mol;

With this amount of zinc, 0.3 x 2 = 0.6 mol of acid will react. This will synthesize 0.3 mol of hydrogen and 0.3 mol of zinc chloride. Let’s calculate the volume of hydrogen. To do this, multiply the amount of substance by the volume of 1 mole of gas (22.4 liters).

V H2 = 0.3 x 22.4 = 6.72 liters;