Determine the volume of hydrogen obtained by the interaction of zinc with hydrochloric acid, the mass of which is 146 g.

1. Let’s illustrate the ongoing reaction:

Zn + 2HCl = ZnCl2 + H2 ↑;

2. Let’s calculate the number of moles of reacted hydrogen chloride:

n (HCl) = m (HCl): M (HCl) = 146: 36.5 = 4 mol;

3. The chemical amounts of the initial hydrochloric acid and the released hydrogen have a ratio of 2: 1, we find the amount of hydrogen:

n (H2) = n (HCl): 2 = 4: 2 = 2 mol;

4. Determine the volume of gas:

V (H2) = n (H2) * Vm = 2 * 22.4 = 44.8 liters.

Answer: 44.8 liters.