Determine the volume of hydrogen released during the interaction of 130 g of zinc hydrochloric acid.

The reaction between zinc metal and hydrochloric acid is described by the following chemical equation:

Zn + 2HCl = ZnCl2 + H2;

Dissolving 1 zinc molecule releases 1 hydrogen molecule.

Let’s calculate the chemical amount of a substance in 13 grams of zinc.

M Zn = 65 grams / mol;

N Zn = 130/65 = 2 mol;

The same amount of hydrogen gas will be released.

Under normal conditions, 1 mole of ideal gas assumes a volume of 22.40 liters.

The volume of hydrogen will be:

V H2 = 2 x 22.40 = 448 liters;