Determine the volume of hydrogen released during the interaction of zinc with a solution of hydrochloric acid weighing 10 grams.

We write down the reaction equation.
Zn + 2HCL = ZnCl2 + H2.
We find the amount of hydrogen chloride substance. For this we use the following formula.
n = m / M.
Where n is the amount of substance.
m is the mass of the substance.
M is the molar mass of the substance.
M (HCl) = 1 + 35.5 = 36.5 g / mol.
n (HCl) = 10 g / 36.5 g / mol = 0.27 mol.
Next, we find the amount of substance released hydrogen.
0.27 mol HCL – x mol H2.
2 mol HCL – 1 mol H2.
Find the unknown value of x.
X = 0.27 × 1 ÷ 2 = 0.135 mol.
Next, we find the volume of hydrogen.
n = V / Vm.
V = n × Vm.
V = 0.135 mol × 22.4 L / mol = 3.024 L.
Answer: V (H2) = 3.024 l.