Determine the volume of hydrogen released when 50 g of 10% acetic acid interacts with magnesium.

Metallic magnesium dissolves in acetic acid solution. The chemical reaction proceeds according to the following equation:

Mg + 2CH3COOH = Mg (CH3COO) 2 + H2 ↑;

Find the chemical amount of acetic acid.

To do this, divide its weight by the weight of 1 mole of acid.

M CH3COOH = 12 x 2 + 16 x 2 + 4 = 60 grams / mol;

N CH3COOH = 50 x 0.1 / 60 = 0.08333 mol;

Half the amount of hydrogen will be obtained and half the amount of magnesium will also be spent.

Let’s calculate the volume of hydrogen.

For this purpose, we multiply the amount of the substance by the volume of 1 mole of gas (which is 22.4 liters).

V H2 = 0.0833 / 2 x 22.4 = 9.333 liters;