Determine the volume of hydrogen released when zinc reacts with 14.6 g of hydrochloric acid.

Given:
m (HCl) = 14.6 g
To find:
V (H2)
Decision:
2HCl + Zn = ZnCl2 + H2
n (HCl) = m / M = 14.6 g * 36.5 g / mol = 0.4 mol
n (HCl): n (H2) = 2: 1
n (H2) = 0.4 mol / 2 = 0.2 mol
V (H2) = n * Vm = 0.2 mol * 22.4 L / mol = 4.48 L
Answer: 4.48 L



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