Determine the volume of hydrogen sulfide formed during the reaction of hydrochloric acid with 2 kg

Determine the volume of hydrogen sulfide formed during the reaction of hydrochloric acid with 2 kg of ore containing 90% iron (II) sulfide.

1. The interaction of hydrochloric acid with iron sulfide proceeds according to the equation:

2HCl + FeS = FeCl2 + H2S ↑;

2.Calculate the mass of iron sulfide:

m (FeS) = w (FeS) * m (ores) = 0.9 * 2000 = 1800 g;

3. find the chemical amount of sulfide:

n (FeS) = m (FeS): M (FeS);

M (FeS) = 56 + 32 = 88 g / mol;

n (FeS) = 1800: 88 = 20.4545 mol;

4.determine the amount of the formed hydrogen sulfide:

n (H2S) = n (FeS) = 20.4545 mol;

5.Calculate the volume of hydrogen sulfide:

V (H2S) = n (H2S) * Vm = 20.4545 * 22.4 = 458.18 liters.

Answer: 458.18 liters.