Determine the volume of hydrogen sulphide required to obtain a medium salt from sodium hydroxide weighing 20 kg.

Given: m (NaOH) = 20kg = 20000g + H2S
Find: V (H2S)
Decision:
1.2NaOH + H2S-> Na2S + 2H2O
2.n (NaOH) = m / M = 20000g / 40 g / mol = 500 mol M (NaOH) = 23 + 16 + 1 = 40 g / mol
3. Let’s make the proportion 500/2 = x / 1 x = 250 mol (H2S)
4.V (H2S) = n * Vm = 250 mol * 22.4 g / mol = 5600 l
Answer: 5600 l



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