Determine the volume of hydrogen under normal conditions, which will be released

Determine the volume of hydrogen under normal conditions, which will be released upon interaction of 0.5 mol of aluminum with hydrochloric acid.

Let’s execute the solution step by step:
1. Let’s write down the reaction equation:
2Al + 6HCl = 2AlCl3 + 3H2 – redox reaction, obtained aluminum chloride and hydrogen gas;
2. We make the proportion according to the reaction equation:
0.5 mol (Al) – X mol (H2);
-2 mol -3 mol from here,
X mol (H2) = 0.5 * 3/2 = 0.75 mol;
3. Let’s calculate the volume of hydrogen according to Avogadro’s law:
V (H2) = 0.75 * 22.4 = 16.8 liters.
Answer: when aluminum interacts with hydrochloric acid, hydrogen is released in a volume of 16.8 liters.