Determine the volume of nitrogen oxide 2 formed during the oxidation of 100 g of ammonia, if the yield is 85%.

| September 7, 2021 | education

Let’s find the amount of ammonia substance by the formula:

n = m: M.

M (NH3) = 17 g / mol.

n = 100 g: 17 g / mol = 5.88 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

4NH3 + 5O2 = 4NO + 6H2O.

According to the reaction equation, 4 mol of ammonia accounts for 4 mol of nitrogen oxide. Substances are in quantitative ratios of 1: 1.

The amount of substance will be the same.

n (NH3) = n (NO) = 5.88 mol.

Find the volume of nitric oxide.

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

V = 5.88 mol × 22.4 L / mol = 131.7 L.

131.7 liters were obtained according to calculations (theoretical yield).

According to the condition, the gas yield was 85%.

Let’s find a practical way out of the product.

131.7 g – 100%,

x g – 85%,

x = (131.7 × 85%): 100% = 111.95 liters.

Answer: 111.95 liters.



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