Determine the volume of nitrogen using the equation: 4NH3 + 3O2 → 2N2 + 6H2O if 10 liters of ammonia reacts.

Determine the volume of nitrogen using the equation: 4NH3 + 3O2 → 2N2 + 6H2O if 10 liters of ammonia reacts. How much oxygen is required to oxidize a given volume of ammonia.

4NH3 + 3O2 → 2N2 + 6H2O
n (NH3) = V \ Vm = 10l \ 22.4 l \ mol = 0.44mol
n (N2) = 0.44 mol * 2 \ 4 = 0.22 mol
V (N2) = n * Vm = 0.22 mol * 22.4 l \ mol = 4.928 l
n (O2) = 0.44 * 3 \ 4 = 0.33 mol
V (O2) = n * Vm = 0.33 mol * 22.4 l \ mol = 7.392 l



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