Determine the volume of so2 that was formed during the combustion of 160g of sulfur containing 20% of impurities.
| December 10, 2020 | education
S + O2 = SO2
sulfur contains 20 percent impurities
let’s make a proportion
160 – 100%
x – 80%
x = 160 * 80/100 = 128 – mass of pure sulfur
n (S) = 128/32 = 4 moles
n (SO2) = 4 moles
1 mol of gas at low takes 22.4 liters
4 moles – 89.6 liters
answer: 89.6 liters
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