Determine the volume of the cavity of a steel ball weighing 3.9 kg if its volume is 550 cm3.

Initial data: m (mass of the steel ball) = 3.9 kg; V (volume of a steel ball with a cavity) = 550 cm ^ 3 = 550 * 10 ^ -6 m ^ 3.

Reference values: ρ (density of steel) = 7800 kg / m ^ 3.

1) Determine the volume of steel in the ball: V1 = m / ρ = 3.9 / 7800 = 0.0005 m ^ 3.

2) Calculate the volume of the cavity in the ball: V2 = V – V1 = 550 * 10 ^ -6 – 0.0005 = 0.00005 m ^ 3 or 50 cm ^ 3.

Answer: The volume of the cavity in the steel ball is 50 cm ^ 3.