Determine the volume of the cavity of a steel ball weighing 3.9 kg if its volume is 550 cm3.

The real volume of the steel ball is calculated by the formula:

V = m / ρ, where m is the mass of the steel ball (m = 3.9 kg), ρ is the density of the steel (ρ = 7800 kg / m³).

Let’s calculate the real volume of the steel ball:

V = m / ρ = 3.9 / 7800 = 0.0005 m³ = 500 cm³.

The volume of the cavity inside the steel ball:

V2 = V1 – V, where V1 is the volume of the steel ball with a cavity (V1 = 550 cm3).

V2 = V1 – V = 550 – 500 = 50 cm³.

Answer: The volume of the cavity of the steel ball is 50 cm³.