Determine the volume of the resulting PF5, if 6.72 liters of fluorine entered the reaction

Let’s write the reaction equation:

2P + 5F2 = 2PF5

Amount of substance F2:

v (F2) = V (F2) / Vm = 6.72 / 22.4 = 0.3 (mol).

According to the reaction equation, for 5 mol of F2, 2 mol of PF5 are formed, therefore:

v (PF5) = v (F2) * 2/5 = 0.3 * 2/5 = 0.12 (mol).

Thus, the volume PF5 measured under normal conditions (n.o.):

V (PF5) = v (PF5) * Vm = 0.12 * 22.4 = 2.688 = 2.7 (l).