Determine the volume of water in the interaction of 320 g of ferric oxide with nitric acid.

univerkov | January 17, 2021 | education

Given:
m (Fe2O3) = 320 g
To find:
V (H2O)
Decision:
Fe2O3 + 6HNO3 = 2Fe (NO3) 3 + 3H2O
n (Fe2O3) = m / M = 320 g / 160 g / mol = 2 mol
n (Fe2O3): n (H2O) = 1: 3
n (H2O) = 2 mol * 3 = 6 mol
V (H2O) = n * Vm = 6 mol * 22.4 L / mol = 134.4 L
Answer: 134.4 L

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