Determine the volume with which calcium oxide with a mass of 16.8 g can react.

univerkov | January 17, 2021 | education

Given:
m (CaO) = 16.8 g
To find:
V (CO2)
Decision:
CaO + CO2 = CaCO3
n (CaO) = m / M = 16.8 g / 56 g / mol = 0.3 mol
n (CaO): n (CO2) = 1: 1
n (CO2) = 0.3 mol
V (CO2) = n * Vm = 0.3 mol * 22.4 l / mol = 6.72 l
Answer: 6.72 L

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