Determine the wavelength of electromagnetic radiation with frequencies of 60 and 1240 Hz in a vacuum.

v1 = 60 Hz.
v2 = 1240 Hz
V = 3 * 10 ^ 8 m / s.
λ1 -?
λ2 -?
Wavelength λ is the distance between the nearest wave crests or the smallest distance between points that oscillate in the same phase.
The wavelength λ is determined by the formula: λ = V / v, where V is the wave propagation speed, v is the wave frequency.
The speed of propagation of electromagnetic radiation in a vacuum is V = 3 * 10 ^ 8 m / s – the speed of propagation of light in a vacuum.
λ1 = 3 * 10 ^ 8 m / s / 60 Hz = 5 * 10 ^ 6 m.
λ2 = 3 * 10 ^ 8 m / s / 1240 Hz = 0.24 * 10 ^ 6 m.
Answer: the wavelengths of the corresponding frequencies are λ1 = 5 * 10 ^ 6 m and λ2 = 0.24 * 10 ^ 6 m.