Determine the wavelength to which the receiver’s oscillatory circuit is tuned, if its capacitance is 5nF

Determine the wavelength to which the receiver’s oscillatory circuit is tuned, if its capacitance is 5nF, and the inductance is 50 μH.

Wavelength:

λ = υ * T, where υ is the speed of propagation of an electromagnetic wave in air (equal to the speed of light υ = C = 3 * 108 m / s), T is the oscillation period (Thompson’s formula).

T = 2 * Π * √ (L * C), where L is the inductance of the coil in the receiver (L = 50 μH = 50 * 10-6 H), C is the capacitance of the capacitor in the receiver (C = 5 nF = 5 * 10- 9 F).

λ = υ * 2 * Π * √ (L * C).

Let’s do the calculation:

λ = 3 * 108 * 2 * 3.14 * √ (50 * 10-6 * 5 * 10-9) = 942 m.

Answer: The oscillating circuit is tuned to a wavelength of 942 m.