Determine the weight of a body weighing 300 g. What is the volume of a body if its density is 7.9 g / cm ^ 3.

Given:

V = 200 cm3 (cubic centimeters) is the volume of a steel part immersed in mercury;

ro = 13500 kg / m3 (kilogram per cubic meter) – the density of mercury.

It is required to determine A (Newton) – buoyancy (Archimedean) force acting on the part.

Let’s convert the units of measurement of volume to the SI system:

V = 200 cm3 = 200 * 10-6 = 2 * 10-4 m3.

Then, to determine the buoyancy force, you must use the following formula:

A = ro * V * g, where g = 10 Newton / kilogram (approximate value);

A = 13500 * 2 * 10-4 * 10;

A = 13500 * 2 * 10-3;

A = 27000 * 10-3 = 27 Newtons.

Answer: A steel part immersed in mercury will have a buoyancy force of 27 Newtons.