Determine the weight of an aluminum cylinder with a volume of 200 cm3 suspended on a strong thread.
| December 7, 2020 | education
Given: p = 2700 kg / m ^ 3, V = 200 cm ^ 3
SI: V = 0.0002 m ^ 3
Find: P
Decision:
P = mg | m = 2700 kg / m ^ 3 * 0.0002 m ^ 3 = 0.54 kg
m = pV | P = 0.54 kg * 9.8 N = 5.2 N
Answer: P = 5.2 N
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