Determine the work if a charge equal to 4.5 * 10 ^ -7 per 20 cm moves in the field, the field strength is 2 * 10 ^ 5H / Kl.

Initial data: q (electric charge value) = 4.5 * 10 ^ -7 C; S (charge movement) = 20 cm = 0.2 m; E (field strength) = 2 * 10 ^ 5 N / C.

The work performed by the forces of the electric field when moving a given charge is determined by the formula: A = E * q * S.

Let’s perform the calculation: A = 2 * 10 ^ 5 * 0.2 * 4.5 * 10 ^ -7 = 0.018 J.

Answer: The work of moving a given charge is 0.018 J.



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