Determine the work of a hoist with a power of 2k W, lifting a load at a speed of 4m / s to a height of 5m.

Np = 2 kW = 2000 W.

V = 4 m / s.

g = 10 N / kg.

h = 5 m.

Ap -?

We express the mechanical work of the elevator Ap by the product of the power of the elevator Np by the time of its operation t: Ap = Np * t.

Since the hoist lifts the load evenly, the operating time of the hoist t for lifting the load is expressed by the ratio of the lifting height h to the speed of its movement V: t = h / V.

The mechanical work of the lift Ap will be determined by the formula: Ap = Np * h / V.

Ap = 2000 W * 5 m / 4 m / s = 2500 J.

Answer: the hoist, when lifting the load, performs mechanical work Ap = 2500 J.