Determine the work of a hoist with a power of 2k W, lifting a load at a speed of 4m / s to a height of 5m.

The work of the lift is determined by the formula:
А = Рt (1), where
P = 2 kW = 2000 W – lift power,
t is the time during which the load is lifted.
We find the time using the following formula:
t = H / v (2), where
H = 5 m – the height to which the load rises,
v = 4 m / s – the speed with which the load is lifted.
We substitute ur-e (2) into ur-e (1) and we get the final formula for work:
A = PH / v
We substitute the given values and find the amount of work:
A = 2000 W x 5 m / (4 m / s) = 2500 J = 2.5 kJ.