Determine the work of an electric current at a current strength of 5.5A, if the consumer’s speed is 1200 Ohm.

Determine the work of an electric current at a current strength of 5.5A, if the consumer’s speed is 1200 Ohm. And it worked 30s. Calculate the power consumed by it.

Task data: I (current strength) = 5.5 A; R (consumer resistance) = 1200 Ohm; t (consumer operating time) = 30 s.

1) Determine the power consumed by the consumer: P = I2 * R = 5.52 * 1200 = 36.3 * 10 ^ 3 W (36.3 kW).

2) Let’s calculate the work of the electric current: Q = I2 * R * t = P * t = 36.3 * 10 ^ 3 * 30 = 1089 * 10 ^ 3 J = 1089 kJ.

Answer: Power consumption is 36.3 kW; the work of the electric current is 1089 kJ.