Determine the work of the friction force if a 200 kg sled moves along a horizontal road

Determine the work of the friction force if a 200 kg sled moves along a horizontal road for 500 m. Friction coefficient 0.1

m = 200 kg.

g = 10 m / s2.

S = 500 m.

∠α = 180 °.

μ = 0.1.

A -?

The work of force A is determined by the formula: A = F * S * cosα, where F is the force that performs the work, S is the movement of the body, ∠α is the angle between the direction of the force F and the movement of S.

Since the friction force Ffr is always directed in the opposite direction of the movement of the body S, then ∠α = 180 °, cos180 ° = – 1.

The friction force Ftr is determined by the formula: Ftr = μ * m * g.

A = – μ * m * g * S.

A = – 0.1 * 200 kg * 10 m / s2 * 500 m = – 100000 J.

Answer: the friction force does the work A = – 100,000 J.