Determine the work performed by a walking excavator if it lifts 14m3 of soil to a height of 20m in one step.

Initial data: V (volume of the raised soil) = 14 m3; h (height of the excavator lifting the soil) = 20 m.

Reference data: ρ (density of loamy soil) = 1750 kg / m3; g (acceleration due to gravity) ≈ 10 m / s2.

The work performed by the walking excavator is determined by the formula: A = F * S = m * g * h = ρ * V * g * h.

Let’s calculate: A = 1750 * 14 * 10 * 20 = 4,900,000 J (4.9 MJ).

Answer: The walking excavator has done work of 4.9 MJ.