Initial data: V (volume of the raised soil) = 14 m3; h (height of the excavator lifting the soil) = 20 m.
Reference data: ρ (density of loamy soil) = 1750 kg / m3; g (acceleration due to gravity) ≈ 10 m / s2.
The work performed by the walking excavator is determined by the formula: A = F * S = m * g * h = ρ * V * g * h.
Let’s calculate: A = 1750 * 14 * 10 * 20 = 4,900,000 J (4.9 MJ).
Answer: The walking excavator has done work of 4.9 MJ.
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