Determine the work performed by the crane with a uniform lifting of a body weighing 3 tons to a height of 7 m.

According to the law of conservation of energy:
A1 = A2, where A1 is the work of the hoist, A2 is the potential energy of the load. I.e:
A1 = mgh = 3000 * 10 * 7 = 210,000J

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