Determine the work performed by the field when moving a point charge of 10 nC from a point with a potential

Determine the work performed by the field when moving a point charge of 10 nC from a point with a potential of 700 V to a point with a potential of 300 V.

Task data: q (value of the moving charge) = 10 nC (10 * 10-9 C); φ1 (potential at the first point of the field) = 700 V; φ2 (potential at the second point of the field) = 300 V.

The work that the field will carry out when the charge moves, we calculate by the formula: A = | q * (φ2 – φ1) |.

Calculation: A = | 10 * 10-9 * (300 – 700) | = 0.000004 J or 4 μJ.

Answer: To move a given charge, the field needed to do a work of 4 μJ.