Determine the work that needs to be done in order to evenly lift a load weighing 2 tons to a height of 5 m.

Answer: 98 kJ.
Explanation of the solution to the problem: to solve the problem, you must use the formula:
A = F * l, where A is the work of the force in J, F is the force of gravity in n, l is the length of the path traveled in m (in our case, this is the height). Besides:
F = m * g, where m is the body weight in kg, g is the acceleration of gravity, g = 9.8 n / kg.
First, you need to translate all known values into the SI system:
m = 2 t = 2 * 1000 = 2000 kg.
Now we substitute all the values into the formula and get:
A = m * g * l = 2000 * 9.8 * 5 = 98000 J = 98 kJ.