Determine the work that the child does by lifting a toy weighing 200 g evenly to a height of 0.5 m.

Problem data: m (mass of a uniformly lifted toy) = 200 g (in SI m = 0.2 kg); h (lifting height) = 0.5 m.

Reference values: g (acceleration due to gravity) ≈ 10 m / s2.

The work that the child has done is equal to the change in the potential energy of the toy: A = ΔEp = m * g * h.

Let’s perform the calculation: A = 0.2 * 10 * 0.5 = 1 J.

Answer: The child’s work when lifting a toy is 1 J.