Determine the work to be done to evenly lift the 10t hydraulic hammer to a height of 150 cm.

Useful work with even lifting of the hydraulic breaker:

A = Ft * h, where Ft is the force of gravity that acts on the hydraulic hammer (Ft = m * g, where m is the mass of the hammer (m = 10 t = 100 00 kg), g is the acceleration due to gravity (we assume g = 10 m / s2)), h – lifting height (h = 150 cm = 1.5 m).

Let’s calculate the useful mechanical work:

A = Ft * h = m * g * h = 10000 * 10 * 1.5 = 150,000 J = 150 kJ.

Answer: With a uniform lifting of the hydraulic hammer, a work of 150 kJ is performed.