Determine the yield of ethyl acetate as a percentage of the theoretical, if the reaction of 30 g of acetic acid

Determine the yield of ethyl acetate as a percentage of the theoretical, if the reaction of 30 g of acetic acid with an excess of ethyl alcohol yields 33 g of the reaction product.

Let’s implement the solution:
1. In accordance with the condition of the problem, we compose the equation:
m = 30 g m = 33 g W -?
CH3COOH + C2H5OH = CH3COO – C2H5 + H2O – esterification, ethyl acetate was obtained;
1 mol 1 mol 1 mol.
2. Calculations:
M (CH3COOH) = 60 g / mol;
M (ether) = 88 g / mol;
Y (CH3COOH) = m / M = 30/60 = 0.5 mol.
3. Find the mass of the product, W:
m (ether) theor. = Y * M = 0.5 * 88 = 44 g;
W = m (practical) / m (theoretical) * 100 = 33/44 * 100 = 75%.
Answer: the ether output was 75%.