Determine the yield of the reaction product if, upon hydration of 14 g of ethylene, 20 g of ethyl alcohol were obtained.

Let’s implement the solution:
1. According to the condition of the problem, we compose the equation:
m = 14 g. m = 20 g. W -?
С2Н4 + Н2О = С2Н5ОН – hydration, ethanol was obtained;
2. Calculation of molar masses:
M (C2H4) = 28 g / mol;
M (C2H5OH) = 46 g / mol.
3. Determine the amount of the original substance:
Y (C2H4) = m / M = 14/28 = 0.5 mol;
Y (C2H5OH) = 0.5 mol since the amount of these substances is equal to 1 mol according to the equation.
4. Find the theoretical mass of the product:
m (C2H5OH) = Y * M = 0.5 * 46 = 23 g.
5. Ethanol yield:
W = m (practical) / m (theoretical) * 100;
W = 20/23 * 100 = 86.95%
Answer: the yield of ethyl alcohol is 86.95%.