Determine what amount of hydrogen sulfide (mol) is formed by the interaction of iron (II)

| September 1, 2021 | education

Determine what amount of hydrogen sulfide (mol) is formed by the interaction of iron (II) sulfide with hydrochloric acid weighing 130 g (mass fraction of HCl is 20%).

1.Let’s find the mass of HCl in the solution.

W = m (substance): m (solution) × 100%,

hence m (substance) = (m (solution) × w): 100%.

m (substance) = (130 g × 20%): 100% = 26 g.

2. Find the amount of HCl substance.

n = m: M.

M (HCl) = 36.5 g / mol.

n = 26 g: 36.5 g / mol = 0.71 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

FeS + 2HCl = FeCl2 + H2S ↑.

According to the reaction equation, there is 1 mol of H2S per 2 mol of HCl. Substances are in quantitative ratios of 2: 1 The amount of H2S substance will be 2 times less than the amount of HCl substance.

n (H2S) = ½ n (HCl) = 0.71: 2 = 0.355 mol.

Answer: 0.355 mol.



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