Determine what mass of hyukoses was subjected to alcoholic fermentation, if the same amount of carbon monoxide
| December 8, 2020 | education
Determine what mass of hyukoses was subjected to alcoholic fermentation, if the same amount of carbon monoxide (4) was released as it is formed during the hollow combustion of methanol with a mass of 16 g.
Reaction equations:
C6H12O6 = 2C2H5OH + 2CO2.
2CH3OH + 3O2 = 2CO2 + 4H2O.
Let’s calculate the amount of alcohol substance:
n = m / M = 16 grams / 32 grams / mol = 0.5 mol.
According to the reaction equation:
n (C6H10O6) = 1 / 2n (CO2) = 0.25 mol.
Let’s calculate the mass of glucose:
m = n * M = 180 grams / mol * 0.25 mol = 45 grams.
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