Determine what mass of lithium oxide can be obtained as a result of the reaction of lithium with 67.2 liters of oxygen.

univerkov | January 17, 2021 | education

Given:
V (O2) = 67.2 l
To find:
m (Li2O)
Decision:
4Li + O2 = 2Li2O
n (O2) = V / Vm = 67.2 L / 22.4 L / mol = 3 mol
n (O2): n (Li2O) = 1: 2
n (Li2O) = 3 mol * 2 = 6 mol
m (Li2O) = n * M = 6 mol * 30 g / mol = 180 g
Answer: 180 g

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