Determine what mass of phosphorus oxide is formed during the combustion of 62 g of phosphorus?

Given:
m (P) = 62 g
To find:
m (P2O5)
Decision:
4P + 5O2 = 2P2O5
n (P) = m / M = 62 g / 31 g / mol = 2 mol
n (P): n (P2O5) = 2: 1
n (P2O5) = 2 mol / 2 = 1 mol
m (P2O5) = n * M = 1 mol * 142 g / mol = 142 g
Answer: 142 g



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