Determine what mass of sulfuric acid H2SO4 can be obtained by reacting 8 g of SO3 with excess water ..?

Given:
m (SO3) = 8 g

To find:
m (H2SO4) -?

1) SO3 + H2O => H2SO4;
2) n (SO3) = m / M = 8/80 = 0.1 mol;
3) n (H2SO4) = n (SO3) = 0.1 mol;
4) m (H2SO4) = n * M = 0.1 * 98 = 9.8 g.

Answer: The mass of H2SO4 is 9.8 g.



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