Determine what volume of hydrogen sulfide is formed by the interaction of 0.5 mol of zinc sulfide

Determine what volume of hydrogen sulfide is formed by the interaction of 0.5 mol of zinc sulfide with 200 cm3 of 20% hydrochloric acid solution.

The reaction of zinc sulfide with hydrochloric acid is described by the following equation:

ZnS + 2HCl = ZnCl2 + H2S;

Let’s determine the molar amount of hydrochloric acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 200 x 0.2 x 1.098 / 36.5 = 1.203 mol;

This will synthesize 1.203 / 2 = 0.6015 mol of hydrogen sulfide.

Let’s find its volume.

To do this, multiply the chemical amount of gas by the volume of 1 mole of ideal gas, which is 22.4 liters.

V H2S = 22.4 x 0.6015 = 13.474 liters;