Determine what volume of hydrogen sulfide is formed by the interaction of zinc sulfide

Determine what volume of hydrogen sulfide is formed by the interaction of zinc sulfide with 190 cm3 of 17% hydrochloric acid solution (density = 1.098 g / cm3)

The reaction of zinc sulfide with hydrochloric acid is described by the following equation:

ZnS + 2HCl = ZnCl2 + H2S;

Let’s calculate the molar amount of hydrochloric acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 190 x 0.17 x 1.098 / 36.5 = 0.972 mol;

In this case, 0.972 / 2 = 0.486 mol of hydrogen sulfide will be formed.

Let’s calculate its volume.

To this end, we multiply the chemical amount of gas by the volume of 1 mole of ideal gas filling the volume of 22.4 liters.

V H2S = 22.4 x 0.486 = 10.886 liters;