Diagonal rhombus 12 cm and 16 cm. Find the side of the rhombus

АС and ВD – diagonals of a rhombus, intersect at point O. АС = 12 cm; BD = 16 cm;
The diagonals of the rhombus intersect at right angles and are halved at the intersection. So triangle AOB is rectangular;
ОВ = 1/2 ВD = 8 cm: AO = 1/2 АС = 6 cm;
AB² = OB² + AO² = 64 + 36 = 100 (cm²);
AB = 10 cm;



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