Diagonals of rectangle ABCD intersect at point O. Find the angle between the diagonals if ∠ABO = 30 °

Since the diagonals in the rectangle are equal, and at the intersection point they are divided in half, OA = OB, and therefore the ABO triangle is isosceles and the angle ABO = ABO = 30. Then the angle AOB = 180 – 30 – 30 = 120.

The angles DOA and AOB are adjacent, then the angle DOA = 180 – 120 = 60.

Answer: The angles between the diagonals are 60 and 120.



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