Diameters AD and BC are drawn in a circle centered at point o, angle OA B is 29. Find the value of angle BDA.

Triangle AOB is isosceles, since OA and OB are circular radii, then the angle AOB = (180 – 2 * 29) = 122. The angles AOB and DOB are adjacent angles, the sum of which is 180, then the angle BOD = 180 – 122 = 58.

Determine the angle DBO. Angle DBO = DBA = (180 – 58) / 2 = 61.

Answer: Angle DBA is 61.



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