Dissolving silver in nitric acid released 560 ml of nitric oxide (II). The mass of the dissolved metal is equal to ..

To solve, we write down the equation of the process:

3Ag + 4HNO3 = 2NO + 3AgNO3 + H2O – OBP, nitrogen oxide is released (2);
We make calculations:
M (Ag) = 107.8 g / mol;

M (HNO3) = 63 g / mol;

V (HNO3) = 560 ml = 0.56 l

3. Proportions:

1 mol of gas at normal level – 22.4 liters;

X mol (HNO3) – 0.56 L from here, X mol (HNO3) = 1 * 0.56 / 22.4 = 0.025 mol;

X mol (Ag) – 0.025 mol (HNO3);

-3 mol – 4 mol from here, X mol (HNO3) = 3 * 0.025 / 4 = 0.018 mol.

Find the mass of the metal:
m (Ag) = Y * M = 0.018 * 107.8 = 1.94 g

Answer: The mass of silver is 1.94 g