Dissolving zinc in acid released 11.2 liters of hydrogen. Determine how much zinc dissolved in acid.

univerkov | July 10, 2021 | education

The general equation for the reaction of zinc with acid is:

Zn + 2H⁺ = Zn²⁺ + H₂

Amount of substance H2:

v (H2) = V (H2) / Vm = 11.2 / 22.4 = 0.5 (mol).

According to the reaction equation, 1 mole of H2 is formed from 1 mole of Zn, therefore:

v (Zn) = v (H2) = 0.5 (mol) and thus

mass of zinc dissolved in acid:

m (Zn) = v (Zn) * M (Zn) = 0.5 * 65 = 32.5 (g).

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