Dissolving zinc in hydrochloric acid produced 13.44 liters of gas. Determine: A. the mass of the reacted zinc

| May 8, 2021 | education

Dissolving zinc in hydrochloric acid produced 13.44 liters of gas. Determine: A. the mass of the reacted zinc B. the mass of the formed salt.

Let’s find the amount of carbon dioxide by the formula:

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

n = V: Vn.

n (H2) = 13.44 L: 22.4 L / mol = 0.6 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

Zn + 2HCl = ZnCl2 + H2.

According to the reaction equation, there is 1 mole of zinc for 1 mole of hydrogen. Substances are in quantitative ratios 1: 1.

The amount of zinc and hydrogen will be the same.

n (Zn) = n (H2) = 0.6 mol.

Let’s find the mass of zinc by the formula:

m = n × M,

M (Zn) = 65 g / mol.

m = 0.6 mol × 65 g / mol = 39 g.

Let’s find the mass of salt – zinc chloride. According to the reaction equation, 1 mole of hydrogen is 1 mole of salt. Substances are in quantitative ratios 1: 1.

The amount of zinc chloride and hydrogen will be the same.

n (ZnCl2) = n (H2) = 0.6 mol.

Find the mass of zinc chloride by the formula:

m = n × M,

M (ZnCl2) = 65 + 70 = 135 g / mol.

m = 0.6 mol × 135 g / mol = 81 g.

Answer: 81 g.



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